Kotlin集合運算子整理總表Iterable/Collection/List/Set/Map

出處 : https://blog.csdn.net/vitaviva/article/details/107587134

建立集合 

不可變更集合 immutable

import java.util.*
import java.text.SimpleDateFormat
/**
 * You can edit, run, and share this code.
 * play.kotlinlang.org
 */
fun main() {
    val list = listOf(1,2,3, null)
    // 不為 null List
    val notNullList = listOfNotNull(null,1,2,3,null)
    val map = mapOf("foo" to "FOO", "bar" to "BAR", "bar" to "BB")
    val set = setOf(4,5,6,6)
    println(list) 			// 	[1, 2, 3, null]
    println(notNullList) 	//	[1, 2, 3]
    println(map)			// 	{foo=FOO, bar=BB}
    println(set)			// 	[4, 5, 6]
}
  

可變更集合 mutable

import java.util.*
import java.text.SimpleDateFormat
/**
 * You can edit, run, and share this code.
 * play.kotlinlang.org
 */
fun main() {
  val list = mutableListOf(1,2,3,3)
  val map = mutableMapOf("foo" to "FOO", "bar" to "BAR", "bar" to "BB")
  val set = mutableSetOf(1,2,3,3)
  println(list) // [1, 2, 3, 3]
  println(map)	// {foo=FOO, bar=BB}
  println(set)	// [1, 2, 3]
}
  

 索引

import java.util.*
import java.text.SimpleDateFormat

fun main() {
	val list = listOf(1,2,3)
    val indices: IntRange = list.indices
    println(indices)
    
    for(i in list.indices){
        println(list[i])
    }
    /*
     0..2
    1
    2
    3
    */
    println(list.first()) 	// 1
    println(list.last())	// 3
    println(list.lastIndex) // 2 = ( size - 1 )
    println(list.size)		// 3
}

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